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Question Number 182910 by mnjuly1970 last updated on 16/Dec/22

Answered by mr W last updated on 16/Dec/22

$$a=sidelengthofsquare$$$$R=radiusofcircle$$$$R^2={(R-a)}^2+{(R-\frac{a}{2})}^2$$$$5a^2-12Ra+4R^2=0$$$$\Rightarrow \frac{a}{R}=\frac{2}{5}$$$$\Rightarrow a=\frac{2}{5}\times 5=2cm$$$$areaofsquare=a^2=4{cm}^2$$

Commented by mnjuly1970 last updated on 16/Dec/22

$$gratefulsirW$$

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