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Question Number 182946 by myint last updated on 17/Dec/22

$$\mathrm{If}0<\mathrm{x}<1,\mathrm{then}\mid \mathrm{x}-1\mid +\mid 2\mathrm{x}-4\mid +\mid 2\mathrm{x}+1\mid =$$

Commented bymr W last updated on 17/Dec/22

$$\ne constantvalue!$$

Answered by Frix last updated on 17/Dec/22

$$0<x<1\Rightarrow x-1<0\wedge 2x-4<0\wedge 2x+1>0\Rightarrow$$ $$\mid x-1\mid +\mid 2x-4\mid +\mid 2x+1\mid =$$ $$=-(x-1)-(2x-4)+2x+1=$$ $$=6-x$$

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