If a< b<0, then ∣a−b∣ + ∣a+b∣ + ∣ab∣=


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Question Number 182947 by myint last updated on 17/Dec/22

$If a < b < 0, then ∣ a - b ∣ + ∣ a + b ∣ + ∣ ab ∣=$
Commented bymr W last updated on 17/Dec/22

$\neq c o n s t a n t v a l u e!$ $c o u l d b e a n y p o s i t i v e v a l u e!$
	Answered by Frix last updated on 17/Dec/22

	$a < b < 0 \Rightarrow a - b < 0 \land a + b < 0 \land a b > 0 \Rightarrow$ $∣ a - b ∣ + ∣ a + b ∣ + ∣ a b ∣=$ $= - (a - b) - (a + b) + a b =$ $= - 2 a + a b = a (b - 2)$
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