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Question Number 182995 by universe last updated on 18/Dec/22

Answered by som(math1967) last updated on 18/Dec/22

Commented by som(math1967) last updated on 18/Dec/22

$$Area=4\times \{{\int }_0^1\sqrt{1-x^2}dx-{\int }_0^1(1-x)dx$$$$=4\times \{\frac{\pi }{4}-(1-\frac{1}{2})\}$$$$=(\pi -2)squnit$$$$\left(d\right)$$

Commented by universe last updated on 18/Dec/22

$$thankssir$$

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