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Question Number 183135 by Tawa11 last updated on 21/Dec/22

Answered by TheSupreme last updated on 21/Dec/22

$$\frac{\mathrm{\Delta }y}{\mathrm{\Delta }h}=\frac{y(x+h)-y\left(x\right)}{h}=\frac{2{(x+h)}^2-2x^2+5h}{h}=$$$$=\frac{2h(2x+h)+5h}{h}=4x+5+2h$$$$x=2$$$$\frac{\mathrm{\Delta }y}{\mathrm{\Delta }h}=13+2h$$$$ifh=0$$$$\frac{\mathrm{\Delta }y}{\mathrm{\Delta }x}=13$$

Commented by Tawa11 last updated on 21/Dec/22

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.\mathrm{I}\mathrm{appreciate}.$$

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