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Question Number 183162 by mnjuly1970 last updated on 21/Dec/22
Answered by aleks041103 last updated on 23/Dec/22
sin(x)=x−x36+o(x3)⇒−sin(x)x=−1+x26+o(x2)→−1+−xsin(x)→−1−⇒⌊−sin(x)x⌋→−1⌊−xsin(x)⌋→−2limx→0±⌊sin(x)⌋+⌊−sin(x)⌋=⌊0±⌋+⌊0∓⌋=={0−1+{−10=−1⇒limx→0⌊−sin(x)x⌋+⌊−xsin(x)⌋⌊sin(x)⌋+⌊−sin(x)⌋=−1+(−2)−1=3limx→0⌊−sin(x)x⌋+⌊−xsin(x)⌋⌊sin(x)⌋+⌊−sin(x)⌋=3
Commented by mnjuly1970 last updated on 29/Dec/22
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