Question Number 183260 by TUN last updated on 24/Dec/22
Answered by greougoury555 last updated on 24/Dec/22
$$\:=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{x}−\mathrm{sin}\:{x}}{{x}^{\mathrm{3}} }\:=\:\frac{\mathrm{1}}{\mathrm{6}} \\ $$
Answered by TheSupreme last updated on 24/Dec/22
$${sin}\left({x}\right)\sim{x}−\frac{{x}^{\mathrm{3}} }{\mathrm{6}}+{o}\left({x}^{\mathrm{4}} \right) \\ $$$${lim}\:...\:=\:\frac{\mathrm{1}}{\mathrm{6}} \\ $$
Commented by TUN last updated on 24/Dec/22
$${no}\:{using}\:{taylor}\:{or}\:{l}'{hospital} \\ $$
Commented by TheSupreme last updated on 24/Dec/22
$${ahahaha}...\:{solve}\:{this}\:{but}\:{don}'{t}\:{use}\:{the}\:{formulas}\:{to}\:{solve}\:{it} \\ $$
Commented by TUN last updated on 24/Dec/22
$${ok} \\ $$