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Question Number 183260 by TUN last updated on 24/Dec/22

	Answered by greougoury555 last updated on 24/Dec/22

	$= \lim_{x \to 0} \frac{x - \sin x}{x^{3}} = \frac{1}{6}$
	Answered by TheSupreme last updated on 24/Dec/22

	$s i n (x) \sim x - \frac{x^{3}}{6} + o (x^{4})$ $l i m . . . = \frac{1}{6}$
	Commented by TUN last updated on 24/Dec/22

	$n o u s i n g t a y l o r o r l^{'} h o s p i t a l$
	Commented by TheSupreme last updated on 24/Dec/22

	$a h a h a h a . . . s o l v e t h i s b u t {d o n}^{'} t u s e t h e f o r m u l a s t o s o l v e i t$
	Commented by TUN last updated on 24/Dec/22

	$o k$
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