{ ((y=sec^n θ−cos^n θ)),((x=sec θ−cos θ)) :} xy ′+(x^2 +y^2 )y′′ =?


Question and Answers Forum

All Questions Topic List
Differentiation Questions
Previous in All Question Next in All Question
Previous in Differentiation Next in Differentiation
Question Number 183447 by greougoury555 last updated on 26/Dec/22
${ ((y=sec^n θ−cos^n θ)),((x=sec θ−cos θ)) :} xy ′+(x^2 +y^2 )y′′ =?$
${\begin{cases} y = \sec^{n} θ - \cos^{n} θ \\ x = \sec θ - \cos θ \end{cases}$ $x y^{'} + (x^{2} + y^{2}) y^{″} = ?$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum