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Question Number 183447 by greougoury555 last updated on 26/Dec/22

  { ((y=sec^n θ−cos^n θ)),((x=sec θ−cos θ)) :}   xy ′+(x^2 +y^2 )y′′ =?

$$\:\begin{cases}{{y}=\mathrm{sec}\:^{{n}} \theta−\mathrm{cos}\:^{{n}} \theta}\\{{x}=\mathrm{sec}\:\theta−\mathrm{cos}\:\theta}\end{cases} \\ $$$$\:{xy}\:'+\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right){y}''\:=? \\ $$

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