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Question Number 183558 by Acem last updated on 27/Dec/22

Commented by Acem last updated on 27/Dec/22

$T h e i n l e t s e g m e n t ⊥ H y p o t e n u s e$
	Answered by HeferH last updated on 27/Dec/22

	$\frac{3}{2} \cdot \frac{2}{5} = \frac{3}{5} = \frac{3 k}{5 k}$ $A = 8 k$
	Commented by Acem last updated on 27/Dec/22

	$H i S i r!$ $w h y \frac{2}{5} ?$
	Commented by HeferH last updated on 27/Dec/22

	$\frac{\frac{3}{2}}{\frac{5}{2}} = \frac{3}{2} \cdot \frac{2}{5}$
	Commented by Acem last updated on 27/Dec/22

	$W e l l m y f r i e n d, a n d w h a t d o e s m e a n \frac{δ}{λ}$
	Commented by HeferH last updated on 27/Dec/22

	$W h e n y o u h a v e a l i n e t h a t g o e s f r o m o n e v e r t e x$ $t o a n y p o i n t o f t h e o p o s i t e s i d e (t r i a n g l e)$ $t h e r a t i o o f t h e b a s e s i s e q u a l t o t h e r a t i o o f$ $t h e i r a r e a s$ $\frac{a}{b} = \frac{A_{1}}{A_{2}} o r \frac{A_{2}}{b} = \frac{A_{1}}{a}$ $O n e i n t e r p r e t a t i o n i s t h a t t h e b a s e$ $i s p r o p o r t i o n a l t o t h e a r e a$ $(i f t h e h e i g h t i s f i x e d)$
	Commented by Acem last updated on 27/Dec/22

	$V e r y g o o d, t h a n k y o u! s o h o w i t h e l p s t o f i n d t h e$ $e n t i r e a r e a o f t h a t t r i a n g l e ?$ $T h e i n l e t s e g m e n t ⊥ H y p o t e n u s e$ $K n o w i n g t h a t i t s a r e a \in] \frac{5}{2}, 4 [$
	Commented by HeferH last updated on 27/Dec/22

	$I t w a s n o t c l e a r t h a t t h e i n l e t s e g m e n t w a s$ $⊥ t o t h e H y p o t e n u s e :)$
	Commented by Acem last updated on 27/Dec/22

	$i f o r g o t t o d r a w t h e m a r k o f i t (: s o r r y!$
	Answered by HeferH last updated on 27/Dec/22

	$h^{2} = \frac{3}{2} \cdot \frac{5}{2} (b y s o m e s i m i l a r t r i a n g l e s)$ $h = \frac{\sqrt{15}}{2} \Rightarrow A = \frac{4 \cdot \frac{\sqrt{15}}{2}}{2} = \sqrt{15}$
	Commented by Acem last updated on 27/Dec/22

	$T h a n k k k k y o u S i r! (:$
	Answered by Acem last updated on 27/Dec/22

	Commented by Acem last updated on 27/Dec/22
	$We must notforget the story of the chord of the circle passing through the vertices of the triangle ω^2 = m.n { 2 segments of the diameter} That if didn′t mind the story of similar triangles$
	$W e m u s t n o t f o r g e t t h e s t o r y o f t h e c h o r d o f t h e$ $c i r c l e p a s s i n g t h r o u g h t h e v e r t i c e s o f t h e t r i a n g l e$ $ω^{2} = m . n {2 s e g m e n t s o f t h e d i a m e t e r}$ $T h a t i f {d i d n}^{'} t m i n d t h e s t o r y o f s i m i l a r t r i a n g l e s$
	Commented by HeferH last updated on 27/Dec/22

	$Y e a h, I r e a l i z e t h a t m a n y t i m e s w h e n I h a d$ $a r e c t t r i a n g l e i n s i d e a c i r c u n f e r e n c e w h i l e$ $w o r k i n g o n o t h e r p r o b l e m s .$ $I t o u g h t i t w a s a c o i n c i d e n c e b u t i t i s a l s o$ $a n o t h e r w a y o f d e m o n s t r a t e i t .$ $S o r r y i f I s o u n d a b i t w e i r d s o m e t i m e s,$ $e n g l i s h i t s n o t m y f i r s t l a n g u a g e : /$
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