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Question Number 183592 by greougoury555 last updated on 27/Dec/22
{xy+yz+zx=3yx+zy+xz=3xyz=1
Answered by mr W last updated on 27/Dec/22
a=xy,b=yz,c=zxabc=1a+b+c=31a+1b+1c=3ab+bc+ca=3a,b,carerootsoft3−3t2+3t−1=0(t−1)3=0⇒a=b=c=t=1⇒x=y=z=1✓
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