y′^(′′) + 8y′^(′′) +12y′ = 0 Solve with better explanation


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Question Number 183600 by Mastermind last updated on 27/Dec/22

$y^{'^{″}} + {8 y}^{'^{″}} + {12 y}^{'} = 0$ $Solve with better explanation$
Commented by mr W last updated on 27/Dec/22

$y o u h a v e c a u s e d o t h e r p e o p l e d o i n g$ $u n n e c e s s a r y w o r k t o s o l v e y o u r$ $q u e s t i o n s w h i c h y o u {d i d n}^{'} t m e a n,$ $b e c a u s e y o u h a d t y p o s, l i k e Q 183209 .$ $s o p l e a s e b e m o r e c a r e f u l w h e n p o s t i n g$ $a q u e s t i o n, c h e c k i f y o u h a v e t y p o s$ $b e f o r e s e n d i n g!$ $i t h i n k y o u h a v e h e r e t y p o s a g a i n :$ $y^{'^{″}} + {8 y}^{'^{″}} + {12 y}^{'} = 0$ $l e t o t h e r p e o p l e d o u n n e c e s s a r y$ $w o r k i s a l s o d i s r e s p e c t f u l!$ $m a k i n g m i s t a k e i s e x c u s a b l e, b u t$ $m a k i n g t h e s a m e m i s t a k e r e p e a t e d l y$ $i s i n e x c u s a b l e!$
Commented by Mastermind last updated on 27/Dec/22

$I understand you BOSS, thank you$
Commented by mr W last updated on 27/Dec/22

$t h e n p l e a s e m a k e y o u r q u e s t i o n c l e a r!$ ${9 y}^{'^{″}} + {12 y}^{'} = 0$ $o r$ $y^{'^{″}} + {8 y}^{″} + {12 y}^{'} = 0$
	Answered by CElcedricjunior last updated on 27/Dec/22

	$y (x) = {a e}^{- 6 x} + {b e}^{- 2 x} + c$ $a; b e t c \in R$
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