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Question Number 183750 by kapoorshah last updated on 29/Dec/22

Answered by mr W last updated on 30/Dec/22

S_1 =a  S_6 =((a(1−q^6 ))/(1−q))  a+((a(1−q^6 ))/(1−q))=1024  a(2−q−q^6 )=1024(1−q)  ((a(1−q^3 ))/(1−q))×((a(1−q^4 ))/(1−q))=1023  ((a^2 (1−q^3 )(1−q^4 ))/((1−q)^2 ))=1023  ((1024^2 (1−q^3 )(1−q^4 ))/((2−q−q^6 )^2 ))=1023  ⇒q≈3.9841  (S_(11) /S_8 )=((1−q^(11) )/(1−q^8 ))≈63.2408

S1=aS6=a(1q6)1qa+a(1q6)1q=1024a(2qq6)=1024(1q)a(1q3)1q×a(1q4)1q=1023a2(1q3)(1q4)(1q)2=102310242(1q3)(1q4)(2qq6)2=1023q3.9841S11S8=1q111q863.2408

Commented by kapoorshah last updated on 30/Dec/22

how to find q ≈ 3.9841

howtofindq3.9841

Commented by mr W last updated on 30/Dec/22

you can only approximate.  i used an app.

youcanonlyapproximate.iusedanapp.

Commented by kapoorshah last updated on 30/Dec/22

what application did you use?

whatapplicationdidyouuse?

Commented by mr W last updated on 30/Dec/22

i used grapher. but there are many  other similar apps you can also use.

iusedgrapher.buttherearemanyothersimilarappsyoucanalsouse.

Commented by kapoorshah last updated on 30/Dec/22

thank you

thankyou

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