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Question Number 183847 by Michaelfaraday last updated on 30/Dec/22

Answered by MJS_new last updated on 31/Dec/22

5x^2 −7x=t  (√(t+10))−(√(t−9))=1  (√(100))−(√(81))=1  t=90  x=−((18)/5)∨x=5

5x27x=tt+10t9=110081=1t=90x=185x=5

Commented by Michaelfaraday last updated on 31/Dec/22

thanks sir

thankssir

Commented by MJS_new last updated on 31/Dec/22

sometimes you need sharp eyes instead of  sharp brains

sometimesyouneedsharpeyesinsteadofsharpbrains

Answered by a.lgnaoui last updated on 31/Dec/22

(√(5x^2 −7x+10)) −(√((5x^2 −7x+10)−19)) )^2 =1  5x^2 −7x+10=z  z+(z−19)−2(√(z(z−19)) =1   (√(z(z−19))) =10−z   z(z−19)=100+z^2 −20z  100−z=0⇒z=100  5x^2 −7x−90=0  △=49+20×90=1849=43^2            x=((7±43)/(10))     x=5  x_1 =5                verification  (√(125−35+10)) −(√(125−35−9)) =10−9=1

5x27x+10(5x27x+10)19)2=15x27x+10=zz+(z19)2z(z19=1z(z19)=10zz(z19)=100+z220z100z=0z=1005x27x90=0=49+20×90=1849=432x=7±4310x=5x1=5verification12535+10125359=109=1

Commented by Michaelfaraday last updated on 31/Dec/22

thanks sir

thankssir

Answered by mr W last updated on 31/Dec/22

a=(√(5x^2 −7x+10))  b=(√(5x^2 −7x−9))  a−b=1  a^2 −b^2 =10−(−9)=19  (a−b)(a+b)=19  a+b=19  ⇒a=((1+19)/2)=10  (√(5x^2 −7x+10))=10  5x^2 −7x+10=10^2   5x^2 −7x−90=0  ⇒x=((7±43)/(10))=−((18)/5), 5 ✓

a=5x27x+10b=5x27x9ab=1a2b2=10(9)=19(ab)(a+b)=19a+b=19a=1+192=105x27x+10=105x27x+10=1025x27x90=0x=7±4310=185,5

Commented by Michaelfaraday last updated on 31/Dec/22

wow,thanks sir

wow,thankssir

Answered by manxsol last updated on 31/Dec/22

(√a)−(√b)=1  ((√a)+(√b))((√a)−(√b))=(√a)+(√b)  (√a)+(√b)=19  add  2(√a)=20⇒  (√a)=10  (√b)=9  5x^2 −7x+10=100  5x^2 −7x−90=0  x1=5  x2=−((18)/5)  5x^2 −7x−9=81  5x^2 −7x−90=0 equal equation  comprobation  x1✓  x2✓  csolution={5,−((18)/5)}

ab=1(a+b)(ab)=a+ba+b=19add2a=20a=10b=95x27x+10=1005x27x90=0x1=5x2=1855x27x9=815x27x90=0equalequationcomprobationx1x2csolution={5,185}

Commented by Michaelfaraday last updated on 31/Dec/22

thanks sir

thankssir

Answered by Rasheed.Sindhi last updated on 31/Dec/22

(√(5x^2 −7x+10)) −(√(5x^2 −7x−9)) =1..(i)  Multiplying by (√(5x^2 −7x+10)) +(√(5x^2 −7x−9)) to both sides:    (5x^2 −7x+10)−(5x^2 −7x−9)            =(√(5x^2 −7x+10)) +(√(5x^2 −7x−9))     (√(5x^2 −7x+10)) +(√(5x^2 −7x−9)) =19...(ii)  (i)+(ii)   2(√(5x^2 −7x+10)) =20  5x^2 −7x+10=100  5x^2 −7x−90=0  (x−5)(5x+18)=0  x=5 ∨ x=−((18)/5)

5x27x+105x27x9=1..(i)Multiplyingby5x27x+10+5x27x9tobothsides:(5x27x+10)(5x27x9)=5x27x+10+5x27x95x27x+10+5x27x9=19...(ii)(i)+(ii)25x27x+10=205x27x+10=1005x27x90=0(x5)(5x+18)=0x=5x=185

Commented by Michaelfaraday last updated on 31/Dec/22

thanks sir

thankssir

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