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Question Number 183850 by paul2222 last updated on 30/Dec/22

$$\underset{\mathbf{n}=1}{\mathbf{\sum }^{\mathrm{\infty }}}\frac{1}{{\mathbf{n}}^3\left(\begin{array}{c}6\mathbf{n}\\ 3\mathbf{n}\end{array}\right)}$$

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