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Question Number 183893 by Sulaymon last updated on 31/Dec/22

Commented by pablo1234523 last updated on 31/Dec/22

$a l s o f r o m t h e g r a p h i t s e e m s l i k e a > b$ $b u t n o n e o f t h e o p t i o n s a t i s f i e s i t$
Commented by mr W last updated on 31/Dec/22

$p l e a s e t r a n s l a t e t h e q u e s t i o n i n t o$ $e n g l i s h!$ $i g u e s s t h e q u e s t i o n i s w h i c h o f t h e$ $e q u a t i o n s o f t h e c i r c l e i s c o r r e c t .$ $e q n . o f c i r c l e {(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ $f r o m t h e g r a p h w e s e e t h a t f o l l o w i n g$ $c o n d i t i o n s m u s t b e f u l f i l l e d :$ $1) a, b > 0$ $2) a < r, b < r \Rightarrow r^{2} > a^{2}, r^{2} > b^{2}$ $3) \sqrt{a^{2} + b^{2}} > r \Rightarrow r^{2} < a^{2} + b^{2}$ $A), B), C) f u l f i l l a l l t h r e e c o n d i t i o n s$ $a n d c o u l d b e c o r r e c t . D) i s w r o n g .$ $m o s t l i k e l y i s A) .$
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