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Question Number 183998 by JDamian last updated on 01/Jan/23

$$\mathrm{Find}\mathrm{the}\mathrm{natural}\mathrm{number}\mathbf{n}such$$$$n=7^a\cdot {17}^{b}a\in \mathbb{N},b\in \mathbb{N}$$$$\mathrm{and}\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{all}\mathrm{its}\mathrm{divisors}(1\mathrm{and}$$$$\mathbf{n}\mathrm{included})\mathrm{is}2456.$$

Commented by Rasheed.Sindhi last updated on 01/Jan/23

$$\overline{)\begin{array}{c}\mathbf{n}=2023=7^1\cdot {17}^2\end{array}}$$$$\underset{-}{\overline{{★}_{★}^{★}\mathbf{Happy}\mathbf{New}{\mathbf{Year}}_{★}^{★}★}}$$

Answered by Rasheed.Sindhi last updated on 01/Jan/23

$$$$$$\overline{)\begin{array}{c}\underset{\underset{\underset{=2456}{1+7+17+119+289+2023}}{\mathcal{S}\mathit{u}\mathit{m}\mathcal{O}\mathit{f}\mathcal{D}ivisors}}{\mathbf{n}=2023=7^1\cdot {17}^2}\end{array}}$$$$$$

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