Question Number 184012 by manolex last updated on 01/Jan/23
$$\mathrm{3}^{{x}} −\mathrm{2}^{{x}} ={x}^{\mathrm{2}} +\mathrm{10} \\ $$$${find} \\ $$$$\left(\mathrm{3}^{{x}} −\mathrm{10}\right)^{\mathrm{2}} \left(\mathrm{2}^{{x}} −\mathrm{1}\right) \\ $$
Commented by Rasheed.Sindhi last updated on 02/Jan/23
$$\mathrm{7}\:....{sorry}\:{typo}\:{in}\:{calculation}! \\ $$
Commented by manolex last updated on 01/Jan/23
$${as}\:{you}\:{did} \\ $$
Commented by manolex last updated on 02/Jan/23
$${ok},\:{then}\:{Happy}\:{new}\:{year},{Sr}.{Rasheed} \\ $$
Commented by Rasheed.Sindhi last updated on 02/Jan/23
$$\boldsymbol{\mathrm{Happy}}\:\boldsymbol{\mathrm{New}}\:\boldsymbol{\mathrm{Year}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{too}},\: \\ $$$$\boldsymbol{\mathrm{sir}}\:\boldsymbol{{manolex}}! \\ $$
Answered by Frix last updated on 01/Jan/23
$$\mathrm{Obviously}\:{x}=\mathrm{3} \\ $$$$\mathrm{27}−\mathrm{8}=\mathrm{9}+\mathrm{10} \\ $$$$\Rightarrow \\ $$$$\left(\mathrm{27}−\mathrm{10}\right)^{\mathrm{2}} \left(\mathrm{8}−\mathrm{1}\right)=\mathrm{17}^{\mathrm{2}} \mathrm{7}=\mathrm{2023} \\ $$
Commented by manolex last updated on 01/Jan/23
$${Happy}\:{new}\:{year}\:{Sr}.\:{Frix} \\ $$
Commented by Frix last updated on 01/Jan/23
$$\mathrm{Happy}\:\mathrm{New}\:\mathrm{Year}\:\mathrm{to}\:\mathrm{you}\:\mathrm{too}! \\ $$