{ ((y^x = 64)),((y^((x + 1)/(x − 1)) = 16)) :} find “x”


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Question Number 184019 by HeferH last updated on 02/Jan/23
${ ((y^x = 64)),((y^((x + 1)/(x − 1)) = 16)) :} find “x”$
${\begin{cases} y^{x} = 64 \\ y^{\frac{x + 1}{x - 1}} = 16 \end{cases}$ $f i n d ‘ ‘ x^{″}$
Commented by a.lgnaoui last updated on 02/Jan/23

$H a p y N e w y e a r$
Commented by Gazella thomsonii last updated on 02/Jan/23

$= {Ha}^{2} e^{2} p^{2} {wy}^{2} r$
	Answered by manolex last updated on 02/Jan/23

	$x l n y = 3 l n 4$ $\frac{x + 1}{x - 1} l n y = 2 l n 4$ $x = \frac{3 (x + 1)}{2 (x - 1)}$ $2 x^{2} - 2 x = 3 x + 3$ $2 x^{2} - 5 x - 3 = 0$ $2 x + 1$ $x - 3$ $2 x + 1 = 0 x = - \frac{1}{2}$ $x - 3 = 0 x = 3$ $c o m p r o b a n d o$ $x_{1} = 3 x_{2} = - \frac{1}{2}$
	Commented by manolex last updated on 02/Jan/23

	$H a p p y n e w y e a r, S r . H e f e r H$
	Commented by HeferH last updated on 02/Jan/23

	$H a p p y n e w y e a r!$ $:)$
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