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Question Number 184066 by Matica last updated on 02/Jan/23
dydx=y(y+2).findy=?
Answered by mr W last updated on 02/Jan/23
∫dyy(y+2)=∫dx∫(1y−1y+2)dy=2∫dxlny−ln(y+2)=2x+C1lnyy+2=2x+C1yy+2=Ce2x⇒y=21−Ce2x−2
Commented by Matica last updated on 02/Jan/23
Ok.Thankyou.
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