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Question Number 184126 by Noorzai last updated on 03/Jan/23

Answered by Rasheed.Sindhi last updated on 03/Jan/23

$$\because \mathrm{KK}\mathrm{\&}\mathrm{KLK}\mathrm{have}\mathrm{same}\mathrm{unit}-\mathrm{digit}$$$$\therefore {\mathrm{K}}^2=10\mathrm{c}+\mathrm{K};\mathrm{c}=0,1,2,...,8$$$$\mathrm{possible}\mathrm{values}\mathrm{for}\mathrm{K}:$$$$\mathrm{K}=1,5,6$$$$\mathrm{KK}=11,55,66$$$$\mathrm{Only}11\times 11\mathrm{is}3-\mathrm{digit}\mathrm{number}$$$$\therefore \mathrm{KK}=11$$$${\mathrm{KK}}^2=121\Rightarrow \mathrm{L}=2$$$$\mathrm{K}+\mathrm{L}=1+2=3$$

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