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Question Number 184175 by mnjuly1970 last updated on 03/Jan/23

Answered by SEKRET last updated on 03/Jan/23

Commented by SEKRET last updated on 03/Jan/23

$$\mathbf{why}.\mathbf{the}\mathbf{picture}\mathbf{uploaded}\mathbf{is}\mathbf{not}$$$$\mathbf{visible}.$$$$$$

Commented by HeferH last updated on 03/Jan/23

$$Youneedtopress\bullet \bullet \bullet andselect‘‘attach{image}^{″}$$$$ifyoudoitinsideafile(‘‘insert{drawing}^{″}$$$$option)itwillnotshow.$$

Commented by SEKRET last updated on 04/Jan/23

$$\mathbf{tkanks}\mathbf{sir}$$

Answered by TheSupreme last updated on 03/Jan/23

$$\lfloor x\rfloor {sin}^2\left(x\right)iscontinuein\mathbb{R}-\mathbb{Z}$$$$\mathrm{\forall }x\in \mathbb{R}-\mathbb{N}$$$$\frac{df}{dx}=2\lfloor x\rfloor sin\left(x\right)cos\left(x\right)=0\to x=k\frac{\pi }{2}\mathrm{\forall }k\in \mathbb{Z}$$$$x_{crit}=k\frac{\pi }{2}$$

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