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Question Number 184242 by Shrinava last updated on 04/Jan/23

Answered by SEKRET last updated on 04/Jan/23

$$\mathbf{metod}\mathbf{Kramer}$$$$\mathbf{det}\left(\mathbf{A}\right)=\left|\begin{array}{ccc}4& -5& 2\\ 3& -2& 7\\ 3& 10& -2\end{array}\right|=-327$$$$\mathbf{det}\left({\mathbf{A}}_1\right)=\left|\begin{array}{ccc}9& -5& 2\\ 8& -2& 7\\ 17& 10& -2\end{array}\right|=-1041$$$$\mathbf{det}\left({\mathbf{A}}_2\right)=\left|\begin{array}{ccc}4& 9& 2\\ 3& 8& 7\\ 3& 17& -2\end{array}\right|=-243$$$$\mathbf{det}\left({\mathbf{A}}_3\right)=\left|\begin{array}{ccc}4& -5& 9\\ 3& -2& 8\\ 3& 10& 17\end{array}\right|=3$$$$\mathbf{x}=\frac{-1041}{-327}=\frac{347}{109}$$$$\mathbf{y}=\frac{-243}{-327}=\frac{81}{109}$$$$\mathbf{z}=\frac{3}{-327}=\frac{-1}{109}$$

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