Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 184656 by Mastermind last updated on 10/Jan/23

$$\mathrm{prove}\mathrm{that}\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{a}\mathrm{triangle}$$$$\mathrm{whose}\mathrm{two}\mathrm{sides}\mathrm{are}\stackrel{-}{\mathrm{A}}\mathrm{and}\stackrel{-}{\mathrm{B}}\mathrm{is}$$$$\mathrm{given}\mathrm{by}\frac{1}{2}\mid \mathrm{A}\times \mathrm{B}\mid .$$$$\mathrm{Also}\mathrm{find}\mathrm{the}\mathrm{direction}-\mathrm{cosine}$$$$\mathrm{of}\mathrm{normal}\mathrm{to}\mathrm{this}\mathrm{area}.$$$$$$$$$$$$\mathrm{Help}!$$

Answered by TheSupreme last updated on 10/Jan/23

$$\mid A\times B\mid =\mid a\mid \mid b\mid sin\left(\theta \right)$$

Commented by TheSupreme last updated on 10/Jan/23

$$directionnormal$$$$\hat{n}=\frac{A\times B}{\mid A\times B\mid }$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com