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Question Number 184822 by mnjuly1970 last updated on 12/Jan/23
Answered by mr W last updated on 12/Jan/23
Commented by mr W last updated on 12/Jan/23
AD=FQ=(4+1)2−(4−1)2=4CE=CD=x−4CB=82+x2EB=82+x2−x+4QB2=42+72=12+(82+x2−x+4)282+x2−x+4=882+x2=4+xx2+64=x2+8x+16⇒x=6✓
Commented by mnjuly1970 last updated on 12/Jan/23
peacebeuponyouSirW
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