Find x in terms of c ∀ 0<c<(2/(3(√3))) (3x^2 −1)(3x^2 +36x−1)^2 ={4(x^3 −x−c)+9(7x^2 +1)}^2


Question and Answers Forum

All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 184828 by ajfour last updated on 12/Jan/23
$Find x in terms of c ∀ 0<c<(2/(3(√3))) (3x^2 −1)(3x^2 +36x−1)^2 ={4(x^3 −x−c)+9(7x^2 +1)}^2$
$F i n d x i n t e r m s o f c \forall 0 < c < \frac{2}{3 \sqrt{3}}$ $(3 x^{2} - 1) {(3 x^{2} + 36 x - 1)}^{2}$ $= {4 (x^{3} - x - c) + 9 (7 x^{2} + 1)}^{2}$
Commented byFrix last updated on 12/Jan/23

$Not possible at all .$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum