Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 184841 by Shrinava last updated on 12/Jan/23

Answered by manolex last updated on 12/Jan/23

$$y=2\sqrt{2}-\sqrt{7}:y=0.18:0<y<1$$$$y^2=15-4\sqrt{14}$$$$\frac{1}{y}=2\sqrt{2}+\sqrt{7}$$$$tenemos$$$$y^x-2y+y^2.\frac{1}{y^x}\ll 0$$$$$$$$\frac{{\left(y^x\right)}^2-2y\left(y^x\right)+y^2}{y^x}\ll 0$$$$\frac{{(y^x-y)}^2}{y^x}\ll 0$$$$y^x>0\Rightarrow {(y^x-y)}^2\ll 0$$$$y^x=y^1$$$$y^x-y=0$$$$\left(y\right)(y^{x-1}-1)=0$$$$y_1=0noroot2\sqrt{2}-\sqrt{7}\ne 1$$$$y^{x-1}=1=y^0$$$$x=1$$$$sum=1$$$$$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com