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Question Number 184872 by CrispyXYZ last updated on 13/Jan/23
Anoddfunctionf(x)whosedomainisRsatisfiesf(x)=f(x+2).Whenx∈(0,1),f(x)=−2x2+ax−2.Iffhas2023zerosin[0,1011].Thentherangeofacanbe?A.[−6,−22]B.[−4,−22]C.[−8,−6]D.[−6,−4]
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![An odd function f(x) whose domain is R satisfies f(x)=f(x+2). When x ∈ (0, 1), f(x)=−2x^2 +ax−2. If f has 2023 zeros in [0, 1011]. Then the range of a can be ? A. [−6, −2(√2)] B. [−4, −2(√2)] C. [−8, −6] D. [−6, −4]](Q184872.png)