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Question Number 184914 by Linton last updated on 13/Jan/23

$$ \\ $$ Lindsey randomly selects 2 distinct days each lveek to go to the gym. Jess randomly selects 3 distinct days each tveek to go to the same gym. What is the probability that Lindsey and Jess will both be at the gym on the same day at least once in any given week? Express your anslver as a common fraction.\\n

Commented bymr W last updated on 04/Mar/23

p=(2/7)×(3/7)=(6/(49))

$${p}=\frac{\mathrm{2}}{\mathrm{7}}×\frac{\mathrm{3}}{\mathrm{7}}=\frac{\mathrm{6}}{\mathrm{49}} \\ $$

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