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Question Number 184959 by Noorzai last updated on 14/Jan/23

Answered by manxsol last updated on 14/Jan/23

$$D)20$$$${AC}^2+5=AB4$$$${AC}^2=A(B-1)9$$$$AC\times A=AC\Rightarrow A=1$$$$1C^2=1(B-1)9$$$$C=3{13}^2=169B-1=6B=7$$$$C=7172=289\times$$$$44-3E=5$$$$44-(30+E)=5$$$$E=9$$$$A=1$$$$B=7$$$$C=3$$$$\mathit{E}=9$$$$Suma=20$$$$$$$$$$

Answered by Rasheed.Sindhi last updated on 14/Jan/23

$$\mathrm{AB}4\mathrm{is}\mathrm{dividend},\mathrm{AC}\mathrm{is}\mathrm{divisor}\mathrm{and}$$$$5\mathrm{is}\mathrm{remainder}.$$$$\underset{―}{44-\mathrm{CE}=05:}$$$$5\mathrm{comes}\mathrm{out}\mathrm{of}(4+\mathrm{borrow}=14)-\mathrm{E}$$$$14-\mathrm{E}=5\Rightarrow \mathrm{E}=9$$$$3-\mathrm{C}=0\Rightarrow \mathrm{C}=3$$$$\underset{\underset{―}{-\mathrm{AC}}}{\mathrm{AB}4}$$$$44$$$$\mathrm{B}-\mathrm{C}=4\Rightarrow \mathrm{B}-3=4\Rightarrow \mathrm{B}=7$$$$\mathrm{AC}\mid \mathrm{CE}\Rightarrow \mathrm{A}3\mid 39\Rightarrow \mathrm{A}=1$$$$\mathrm{A}+\mathrm{B}+\mathrm{C}+\mathrm{E}=1+7+3+9=20$$

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