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Question Number 184989 by Ml last updated on 15/Jan/23

$$2^{\mathrm{x}}=4\mathrm{x}$$$$\mathrm{x}=?$$$$\mathrm{solution}???$$

Answered by Frix last updated on 15/Jan/23

$$2^x=4x$$$$x=-\frac{t}{\ln 2}$$$${\mathrm{e}}^{-t}=-\frac{4t}{\ln 2}$$$${\mathrm{e}}^{t}t=-\frac{\ln 2}{4}$$$$t=W(-\frac{\ln 2}{4})$$$$t=\ln \frac{1}{16}\vee t\approx -.214811$$$$\Rightarrow x=4\vee x\approx .309907$$

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