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Question Number 185073 by emmanuelson123 last updated on 16/Jan/23

Answered by Frix last updated on 16/Jan/23

$$16°{52}^{\prime }{30}^{″}=\frac{3\pi }{32}$$$$\sin \frac{3\pi }{8}=\frac{\sqrt{2+\sqrt{2}}}{2}$$$$\sin \frac{x}{2}=\sqrt{\frac{1-\sqrt{1-{\sin }^{2}x}}{2}}$$$$\sin \frac{3\pi }{16}=\frac{\sqrt{2-\sqrt{2-\sqrt{2}}}}{2}$$$$\sin \frac{3\pi }{32}=\frac{\sqrt{2-\sqrt{2+\sqrt{2-\sqrt{2}}}}}{2}$$

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