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Question Number 185224 by alcohol last updated on 18/Jan/23
Answered by hafiz last updated on 18/Jan/23
Answered by Rasheed.Sindhi last updated on 19/Jan/23
Letthereare100familiesinthetown.Letyfamilieshavebothcar&phone60familieshaveneither..25−yhaveonlyphones20−yhaveonlycarsyhaveboth60+(25−y)+(20−y)+y=100105−y=100⇒y=55%havebothLettherearexfamiliesinthetown5%ofx=20005100x=2000x=2000×1005=40000a.40000familiesinthetownb(1)P∩C=5%(2)24000(3)6000(4)8000
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