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Question Number 18523 by Tinkutara last updated on 23/Jul/17

Match the following  Column-I (Trigonometric equation)  (A) sin 9θ = cos ((π/2) − θ)  (B) sin 5θ = sin ((π/2) + 2θ)  (C) cos 11θ = cos 3θ  (D) 3 tan (θ − 15°) = tan (θ + 15°)  Column-II (Family of solutions)  (p) (2n + 1)(π/(10)), n ∈ Z  (q) ((nπ)/2) + (−1)^n (π/4), n ∈ Z  (r) ((nπ)/7), n ∈ Z  (s) (4n + 1)(π/(14)), n ∈ Z

$$\mathrm{Match}\:\mathrm{the}\:\mathrm{following} \\ $$$$\boldsymbol{\mathrm{Column}}-\boldsymbol{\mathrm{I}}\:\left(\boldsymbol{\mathrm{Trigonometric}}\:\boldsymbol{\mathrm{equation}}\right) \\ $$$$\left(\mathrm{A}\right)\:\mathrm{sin}\:\mathrm{9}\theta\:=\:\mathrm{cos}\:\left(\frac{\pi}{\mathrm{2}}\:−\:\theta\right) \\ $$$$\left(\mathrm{B}\right)\:\mathrm{sin}\:\mathrm{5}\theta\:=\:\mathrm{sin}\:\left(\frac{\pi}{\mathrm{2}}\:+\:\mathrm{2}\theta\right) \\ $$$$\left(\mathrm{C}\right)\:\mathrm{cos}\:\mathrm{11}\theta\:=\:\mathrm{cos}\:\mathrm{3}\theta \\ $$$$\left(\mathrm{D}\right)\:\mathrm{3}\:\mathrm{tan}\:\left(\theta\:−\:\mathrm{15}°\right)\:=\:\mathrm{tan}\:\left(\theta\:+\:\mathrm{15}°\right) \\ $$$$\boldsymbol{\mathrm{Column}}-\boldsymbol{\mathrm{II}}\:\left(\boldsymbol{\mathrm{Family}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{solutions}}\right) \\ $$$$\left(\mathrm{p}\right)\:\left(\mathrm{2}{n}\:+\:\mathrm{1}\right)\frac{\pi}{\mathrm{10}},\:{n}\:\in\:{Z} \\ $$$$\left(\mathrm{q}\right)\:\frac{{n}\pi}{\mathrm{2}}\:+\:\left(−\mathrm{1}\right)^{{n}} \frac{\pi}{\mathrm{4}},\:{n}\:\in\:{Z} \\ $$$$\left(\mathrm{r}\right)\:\frac{{n}\pi}{\mathrm{7}},\:{n}\:\in\:{Z} \\ $$$$\left(\mathrm{s}\right)\:\left(\mathrm{4}{n}\:+\:\mathrm{1}\right)\frac{\pi}{\mathrm{14}},\:{n}\:\in\:{Z} \\ $$

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