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Question Number 185270 by Mingma last updated on 19/Jan/23

Answered by mr W last updated on 20/Jan/23

2a+1≤d≤9 ⇒a≤4 ∩ a≠0 2d=10+a a=4: d=7 ⇒2×4+1=9 > 7 ⇒rejected a=2: d=6 ⇒2×2+1=5 <6 ⇒ok 2(2bc6)+1000=6cb2 2(2000+100b+10c+6)+1000=6000+100c+10b+2 19b−8c=99 19(b−1)=8(10+c) ⇒b=9, c=9 ⇒the number is 2996 ✓

2a+1⩽d⩽9⇒a⩽4∩a≠02d=10+aa=4:d=7⇒2×4+1=9>7⇒rejecteda=2:d=6⇒2×2+1=5<6⇒ok2(2bc6)+1000=6cb22(2000+100b+10c+6)+1000=6000+100c+10b+219b−8c=9919(b−1)=8(10+c)⇒b=9,c=9⇒thenumberis2996✓

Commented by Rasheed.Sindhi last updated on 21/Jan/23

e^x cellent sir!

excellentsir!

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