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Question Number 185310 by mathlove last updated on 20/Jan/23

Commented by HeferH last updated on 20/Jan/23

$$sumadesumas?$$

Answered by Rasheed.Sindhi last updated on 20/Jan/23

$$k^{2}comesktimesingrandtotal.$$$$1^2.1+2^2.2+3^2.3+...{14}^2.14+{15}^2.15$$$$=1^3+2^3+3^3+...+{15}^3$$$$={(1+2+3+...+15)}^2$$$$={\left(\frac{15\times 16}{2}\right)}^2={120}^2=14400$$$$Formulaused:$$$$\overline{)\begin{array}{c}{1}^3+2^3+3^3+...+n^3={\left(\frac{n(n+1)}{2}\right)}^2\end{array}}$$

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