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Question Number 185337 by Shrinava last updated on 20/Jan/23
Answered by qaz last updated on 20/Jan/23
∑nk=2k+kk∼∫2nx+xxdx∼n∑nk=2k+k3k∼∫2nx+x3kdx∼n∑nk=2k+k5k∼∫2nx+x5xdx∼n∑nk=2k2∼13n3⇒Ω=3
Commented by Shrinava last updated on 23/Jan/23
Thankyoudearprofessor,isthereanyothersolution?
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