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Question Number 185394 by mathlove last updated on 21/Jan/23

Answered by mr W last updated on 21/Jan/23

$$P\times (3^{2^0}-1)=(3^{2^1}-1)(3^{2^1}+1)...(3^{2^n}+1)$$$$...$$$$P\times (3^{2^0}-1)=(3^{2^n}-1)(3^{2^n}+1)$$$$P\times (3^{2^0}-1)=3^{2^{n+1}}-1$$$$\Rightarrow P=\frac{3^{2^{n+1}}-1}{3^{2^0}-1}=\frac{3^{2^{n+1}}-1}{2}$$

Commented by mathlove last updated on 21/Jan/23

$$thanks$$

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