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Question Number 185414 by Safiullah_21 last updated on 21/Jan/23

2^x =a  3^y =b      : 6^(xy) =?  ⇒6^(xy) =(2×3)^(xy) ⇒2^(xy) ×3^(xy) ⇒(2^x )^y ×(3^y )^x ⇒a^y ×b^x

2x=a3y=b:6xy=?6xy=(2×3)xy2xy×3xy(2x)y×(3y)xay×bx

Commented by mr W last updated on 21/Jan/23

is a^y b^x  better than 6^(xy)  ?

isaybxbetterthan6xy?

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