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Question Number 185420 by Ml last updated on 21/Jan/23

Commented by Frix last updated on 21/Jan/23

$$\mathrm{I}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{think}\mathrm{this}\mathrm{can}\mathrm{be}\mathrm{simplified}.$$

Answered by malwan last updated on 24/Jan/23

$$\left({}^3\sqrt{4-{}^3\sqrt{2}}\right)({}^3\sqrt{2^2}+{}^3\sqrt{2}+1)$$

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