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Question Number 185522 by Mingma last updated on 23/Jan/23

Commented by Frix last updated on 23/Jan/23

This only requires  r=(D/(2(a+b+c)))  R=((abc)/D)  D=(√((a+b+c)(b+c−a)(a+c−b)(a+b−c)))

$$\mathrm{This}\:\mathrm{only}\:\mathrm{requires} \\ $$$${r}=\frac{{D}}{\mathrm{2}\left({a}+{b}+{c}\right)} \\ $$$${R}=\frac{{abc}}{{D}} \\ $$$${D}=\sqrt{\left({a}+{b}+{c}\right)\left({b}+{c}−{a}\right)\left({a}+{c}−{b}\right)\left({a}+{b}−{c}\right)} \\ $$

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