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Question Number 185708 by mokys last updated on 26/Jan/23

Answered by mr W last updated on 26/Jan/23

$$t=4{\log }_{2}x=\frac{4\ln x}{\ln 2}$$$$dt=\frac{4}{x\ln 2}dx$$$${\int }_1^8\frac{f\left(4{\log }_{2}x\right)}{x}dx$$$$=\frac{\ln 2}{4}{\int }_0^{12}f\left(t\right)dt$$$$=\frac{\ln 2}{4}\times 20$$$$=5\ln 2$$

Commented by mokys last updated on 27/Jan/23

$$thankyousir$$$$$$

Answered by Rajpurohith last updated on 26/Jan/23

Commented by mokys last updated on 27/Jan/23

$$thankyousir$$

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