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Question Number 185781 by Mingma last updated on 27/Jan/23

Answered by ajfour last updated on 27/Jan/23

let BE=4p ,  BD=4q  F(3p,q)  ;   G(3p+(3/4), q+1)  FG=(√((9/(16))+1))=(5/4)

$${let}\:{BE}=\mathrm{4}{p}\:,\:\:{BD}=\mathrm{4}{q} \\ $$$${F}\left(\mathrm{3}{p},{q}\right)\:\:;\:\:\:{G}\left(\mathrm{3}{p}+\frac{\mathrm{3}}{\mathrm{4}},\:{q}+\mathrm{1}\right) \\ $$$${FG}=\sqrt{\frac{\mathrm{9}}{\mathrm{16}}+\mathrm{1}}=\frac{\mathrm{5}}{\mathrm{4}} \\ $$

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