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Question Number 185793 by Rupesh123 last updated on 27/Jan/23
Answered by cortano1 last updated on 28/Jan/23
$$\frac{\mathrm{2}}{{x}+\mathrm{1}}\:=\frac{\mathrm{1}}{\mathrm{5}}\Rightarrow{x}=\mathrm{9} \\ $$$${f}\left(\frac{\mathrm{1}}{\mathrm{5}}\right)=\:\mathrm{9}^{\mathrm{2}} −\mathrm{1}=\mathrm{80} \\ $$
Answered by CElcedricjunior last updated on 27/Jan/23
$$\boldsymbol{{f}}\left(\frac{\mathrm{2}}{\boldsymbol{{x}}+\mathrm{1}}\right)=\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{1} \\ $$$$\boldsymbol{{f}}\left(\frac{\mathrm{2}}{\mathrm{9}+\mathrm{1}}\right)=\mathrm{9}^{\mathrm{2}} −\mathrm{1}=>\boldsymbol{{f}}\left(\frac{\mathrm{2}}{\mathrm{10}}\right)=\mathrm{81}−\mathrm{1} \\ $$$$=>\boldsymbol{{f}}\left(\frac{\mathrm{1}}{\mathrm{5}}\right)=\mathrm{80} \\ $$$$==================== \\ $$$$..................{cedric}\:{junior}\:.............. \\ $$