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Question Number 185873 by test1234 last updated on 29/Jan/23

(1) ∫πx^2 +(√((xe^π )/x^2 ))dx=?  (2) ∫((ln (x)+ln (((−z)/x)))/x^z )+z^x dx=?

(1)πx2+xeπx2dx=?(2)ln(x)+ln(zx)xz+zxdx=?

Answered by JDamian last updated on 29/Jan/23

(2)∫((ln (x((−z)/x)))/x^z )+e^(x∙ln z) dx=  =ln (−z)∫x^(−z) dx+(e^(x∙ln z) /(ln z))

(2)ln(xzx)xz+exlnzdx==ln(z)xzdx+exlnzlnz

Answered by aba last updated on 29/Jan/23

(1)∫πx^2 +(√((xe^π )/x^2 ))dx=∫(πx^2 +(√e^π ).x^(−(1/2)) )dx                                         =(1/3)πx^3 +2(√(e^π x))+k

(1)πx2+xeπx2dx=(πx2+eπ.x12)dx=13πx3+2eπx+k

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