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Question Number 185873 by test1234 last updated on 29/Jan/23
(1)∫πx2+xeπx2dx=?(2)∫ln(x)+ln(−zx)xz+zxdx=?
Answered by JDamian last updated on 29/Jan/23
(2)∫ln(x−zx)xz+ex⋅lnzdx==ln(−z)∫x−zdx+ex⋅lnzlnz
Answered by aba last updated on 29/Jan/23
(1)∫πx2+xeπx2dx=∫(πx2+eπ.x−12)dx=13πx3+2eπx+k
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