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Question Number 185933 by aymanadnan last updated on 30/Jan/23

Answered by qaz last updated on 30/Jan/23

dV=2(y^2 −x^2 )d(y^2 −x^2 )=4(y^2 −x^2 )(ydy−xdx) ⇒V_x =4x(x^2 −y^2 ) V_y =4y(y^2 −x^2 ) ⇒yV_x +xV_y =0

dV=2(y2−x2)d(y2−x2)=4(y2−x2)(ydy−xdx)⇒Vx=4x(x2−y2)Vy=4y(y2−x2)⇒yVx+xVy=0

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