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Question Number 185981 by mnjuly1970 last updated on 30/Jan/23
solveinR⌊2x⌋+⌊3x⌋=1⌊x⌋:=greatestintegernumbermorethanorequalto″x″
Answered by mr W last updated on 30/Jan/23
x=n+f5n+⌊2f⌋+⌊3f⌋=11−5n=⌊2f⌋+⌊3f⌋⩾0⇒n⩽01−5n=⌊2f⌋+⌊3f⌋<5⇒n⩾0⇒n=0⇒0⩽x<12x<1⇒x<121⩽3x<2⇒13⩽x<23⇒13⩽x<12✓
Commented by mnjuly1970 last updated on 31/Jan/23
merceysirW..
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