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Question Number 185985 by cortano1 last updated on 30/Jan/23
∫dxsinx(1+cosx)=?
Answered by ARUNG_Brandon_MBU last updated on 30/Jan/23
I=∫dxsinx(1+cosx)=∫dx2sinx2cos3x2=∫12sec2x2tanx2dx=∫d(tanx2)tanx2=2tanx2+C
Answered by Gamil last updated on 31/Jan/23
Commented by ARUNG_Brandon_MBU last updated on 31/Jan/23
2cscx+cotx=21+cosxsinx=22sinx2cosx22cos2x2=2tanx2
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