prove that(using Epsilon−Delta definition) (a) lim_(x→1) (6x−2)=4 (b)lim


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Question Number 186021 by Spillover last updated on 30/Jan/23

$p r o v e t h a t (u s i n g E p s i l o n - D e l t a d e f i n i t i o n)$ $(a) \lim_{x \to 1} (6 x - 2) = 4$ $(b) \lim_{x \to 6} \sqrt{3 x - 2} = 4$
	Answered by aba last updated on 30/Jan/23

	$\lim_{x \to 1} (6 x - 2) = 6 (1) - 2) = 4$ $\lim_{x \to 6} \sqrt{3 x - 2} = \sqrt{3 (6) - 2} = \sqrt{18 - 2} = 4$
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