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Question Number 18603 by Tinkutara last updated on 25/Jul/17

The work function of a metal is 4 eV. If  light of frequency 2.3 × 10^(15)  Hz is  incident on metal surface, then,  (1) No photoelectron will be ejected  (2) 2 photoelectron of zero kinetic  energy are ejected  (3) 1 photoelectron of zero kinetic  energy is ejected  (4) 1 photoelectron is ejected, which  required the stopping potential of 5.52  volt

$$\mathrm{The}\:\mathrm{work}\:\mathrm{function}\:\mathrm{of}\:\mathrm{a}\:\mathrm{metal}\:\mathrm{is}\:\mathrm{4}\:\mathrm{eV}.\:\mathrm{If} \\ $$$$\mathrm{light}\:\mathrm{of}\:\mathrm{frequency}\:\mathrm{2}.\mathrm{3}\:×\:\mathrm{10}^{\mathrm{15}} \:\mathrm{Hz}\:\mathrm{is} \\ $$$$\mathrm{incident}\:\mathrm{on}\:\mathrm{metal}\:\mathrm{surface},\:\mathrm{then}, \\ $$$$\left(\mathrm{1}\right)\:\mathrm{No}\:\mathrm{photoelectron}\:\mathrm{will}\:\mathrm{be}\:\mathrm{ejected} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{2}\:\mathrm{photoelectron}\:\mathrm{of}\:\mathrm{zero}\:\mathrm{kinetic} \\ $$$$\mathrm{energy}\:\mathrm{are}\:\mathrm{ejected} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{1}\:\mathrm{photoelectron}\:\mathrm{of}\:\mathrm{zero}\:\mathrm{kinetic} \\ $$$$\mathrm{energy}\:\mathrm{is}\:\mathrm{ejected} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{1}\:\mathrm{photoelectron}\:\mathrm{is}\:\mathrm{ejected},\:\mathrm{which} \\ $$$$\mathrm{required}\:\mathrm{the}\:\mathrm{stopping}\:\mathrm{potential}\:\mathrm{of}\:\mathrm{5}.\mathrm{52} \\ $$$$\mathrm{volt} \\ $$

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