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Question Number 186124 by Rupesh123 last updated on 01/Feb/23

Commented by MJS_new last updated on 01/Feb/23

$$3^2+4^2=25\Rightarrow \mathrm{I}\mathrm{guess}y\in \{3,4\}$$$$\mathrm{with}y=4\Rightarrow x=\frac{215}{106}\pm \frac{27\sqrt{17}}{106}\mathrm{i}$$$$\Rightarrow y=3$$

Answered by MJS_new last updated on 01/Feb/23

$$x=\frac{12}{5}y=3z=\frac{18}{5}$$$$xyz=\frac{648}{25}$$

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